How to check if a string contains an other in #bash
Quick trick using #grep in #bash for checking if a string is contained in an other one
STRING="someUnknownString";
NAIL="know";
res=`echo $STRING | grep $NAIL`;
if [[ ${#res} > 0 ]];
then
echo "Yes I found it.";
else
echo "No way, there isn't."
fi
If you want you can make the whole thing case insensitive just using grep -i
STRING="someUnknownString";
NAIL="Unkn";
res=`echo $STRING | grep -i $NAIL`;
if [[ ${#res} > 0 ]];
then
echo "Yes I found it.";
else
echo "No way, there isn't."
fi
Lorenzo Sfarra on IdentiCa suggested me a quicker way to obtain the same result with less code. You can find this nicer way below…
STRING="someUnknownString"; NAIL="Unkn"; echo $STRING | grep -qi $NAIL && echo "Yes, I found it." || echo "no way, there isn't."